What Students Should Master in This Unit
Circular motion connects kinematics, dynamics, and astronomy. Students learn that an object moving in a circle is accelerating even if its speed is constant, because its velocity direction keeps changing.
Use radius, period, frequency, speed, angular speed, and centripetal acceleration.
Identify which real force provides the required centripetal force in each situation.
Use Newton's law of gravitation to explain planetary, moon, and satellite motion.
Jump to a Topic
1. Circular Motion Basics
An object is in circular motion when it moves along a circular path. Even if the speed is constant, velocity changes because direction changes. A change in velocity means acceleration.
Velocity and Acceleration Directions
- Velocity is tangent to the circle.
- Centripetal acceleration points toward the center.
- Centripetal means center-seeking.
- For uniform circular motion, speed is constant but velocity changes direction.
2. Period and Frequency
Period and frequency describe how fast cycles repeat.
Examples
- If a wheel makes 4 revolutions per second, frequency is 4 Hz.
- If a satellite takes 5400 s for one orbit, its period is 5400 s.
- If frequency increases, period decreases.
3. Angular Motion
Angular quantities describe how an object rotates around a center. Radians are the natural angle unit for circular motion.
4. Centripetal Acceleration
Centripetal acceleration is the inward acceleration needed to keep an object moving in a circular path.
5. Centripetal Force
Centripetal force is not a separate kind of force. It is the name for the net inward force required for circular motion.
Free-Body Diagram Rule
Do not draw "centripetal force" as an extra force unless the problem specifically labels a real force that way. Draw real forces first, then set the inward net force equal to mv2/r.
6. Sources of Centripetal Force
Different situations use different real forces to provide the inward net force.
| Situation | Real Force Toward Center | Typical Equation |
|---|---|---|
| Ball on a string | Tension | T = mv2/r |
| Car turning on flat road | Static friction | fs = mv2/r |
| Satellite orbiting Earth | Gravity | Fg = mv2/r |
| Roller coaster loop | Weight, normal force, or both | ΣFinward = mv2/r |
| Object against circular wall | Normal force | FN = mv2/r |
7. Vertical Circles
In vertical circular motion, the force situation changes at the top, bottom, and sides of the circle because weight always points downward while inward direction changes.
8. Banked Curves
A banked curve tilts the road so part of the normal force points toward the center of the turn. This helps vehicles turn without relying entirely on friction.
9. Universal Gravitation
Newton's law of universal gravitation says that every mass attracts every other mass. The force grows with mass and decreases with the square of distance.
Inverse-Square Meaning
If the distance between two masses doubles, gravitational force becomes one-fourth as strong. If the distance triples, force becomes one-ninth as strong.
10. Orbital Motion
A satellite stays in orbit because gravity provides the centripetal force. The satellite is constantly falling toward Earth while moving forward fast enough to keep missing the ground.
11. Simulation Labs for This Unit
These official PhET simulations help students visualize gravitational force, circular motion, orbit stability, orbital speed, mass effects, and multi-body interactions.
Explore how gravity controls circular and orbital motion for planets, moons, and satellites. Students can adjust mass, velocity, and distance to observe orbit changes.
Lab idea: increase orbital speed and observe whether the orbit becomes larger, smaller, or unstable.Build simple gravitational systems and observe how mass, initial speed, and position affect orbital paths and system stability.
Lab idea: create a stable two-body orbit, then change one body's velocity and record what happens.12. Circular Motion and Gravitation Lab Skills
Labs in this unit often involve measuring radius, period, mass, speed, and force. Students should be able to compare measured centripetal force with the value predicted by mv2/r.
Common Labs
- Whirling stopper or rubber stopper circular motion lab.
- Turntable and friction lab.
- Banked curve or flat curve model car lab.
- Simulation-based orbit stability lab.
- Period-radius relationship investigation.
Useful Measurements
- Radius in meters.
- Time for multiple revolutions.
- Period and frequency.
- Mass in kilograms.
- Speed in meters per second.
- Force in newtons.
13. Worked Examples
A toy car moves in a circle of radius 2.0 m with period 4.0 s. Find tangential speed.
v = 2πr/T = 2π(2.0)/4.0 = 3.14 m/s.
A 0.50 kg object moves at 6.0 m/s in a circle of radius 3.0 m. Find centripetal acceleration.
ac = v2/r = 6.02/3.0 = 12 m/s2.
Using the object in example 2, find centripetal force.
Fc = mac = (0.50)(12) = 6.0 N inward.
A car turns on a flat curve of radius 40 m. If μs = 0.60, find maximum speed before skidding.
Static friction provides centripetal force: μsmg = mv2/r.
vmax = √(μsrg) = √[(0.60)(40)(9.8)] = 15.3 m/s.
Two 1000 kg objects are separated by 2.0 m. Find the gravitational force between them.
F = Gm1m2/r2.
F = (6.67 × 10-11)(1000)(1000)/(2.0)2 = 1.67 × 10-5 N.
A satellite orbits Earth at radius 6.77 × 106 m from Earth's center. Use GMEarth = 3.99 × 1014 m3/s2. Find orbital speed.
v = √(GM/r).
v = √[(3.99 × 1014)/(6.77 × 106)] = 7.68 × 103 m/s.
14. Practice Problems
Try each problem first. Then open the answer check and compare formulas, units, and direction reasoning.
1. A wheel has radius 0.40 m and period 2.0 s. Find tangential speed.
Answer
v = 2πr/T = 2π(0.40)/2.0 = 1.26 m/s.
2. A fan spins at 5.0 revolutions per second. Find frequency and period.
Answer
f = 5.0 Hz. T = 1/f = 0.20 s.
3. An object moves at 10 m/s in a circle of radius 5.0 m. Find centripetal acceleration.
Answer
ac = v2/r = 100/5.0 = 20 m/s2.
4. A 2.0 kg object has centripetal acceleration 12 m/s2. Find centripetal force.
Answer
Fc = mac = (2.0)(12) = 24 N inward.
5. A 1.5 kg mass moves at 4.0 m/s on a string of radius 0.80 m. Find tension if tension is the only inward force.
Answer
T = mv2/r = (1.5)(4.0)2/0.80 = 30 N.
6. What direction is velocity in uniform circular motion?
Answer
Tangent to the circular path.
7. What direction is centripetal acceleration?
Answer
Toward the center of the circle.
8. A flat curve has radius 30 m and μs = 0.50. Find maximum speed.
Answer
vmax = √(μsrg) = √[(0.50)(30)(9.8)] = 12.1 m/s.
9. A banked curve has radius 50 m and angle 20 degrees. Find ideal speed with no friction.
Answer
v = √(rg tanθ) = √[(50)(9.8)tan(20)] = 13.4 m/s.
10. A roller coaster loop has radius 12 m. Find minimum speed at the top to maintain contact.
Answer
vmin = √(gr) = √[(9.8)(12)] = 10.8 m/s.
11. If orbital radius increases, what generally happens to orbital speed?
Answer
Orbital speed decreases for circular orbits around the same central mass.
12. Two masses attract with gravitational force F. If distance doubles, what is the new force?
Answer
F/4 because gravity follows an inverse-square relationship.
13. Two masses attract with force F. If one mass doubles and distance stays the same, what is the new force?
Answer
2F.
14. A satellite has orbital radius 8.0 × 106 m. Use GM = 3.99 × 1014 m3/s2. Find orbital speed.
Answer
v = √(GM/r) = √[(3.99 × 1014)/(8.0 × 106)] = 7.06 × 103 m/s.
15. What real force provides centripetal force for a satellite orbiting Earth?
Answer
Gravity.
16. In the Gravity and Orbits simulation, what happens if orbital speed is too low?
Answer
The object falls inward toward the central body instead of maintaining a stable orbit.
15. What to Know Before Moving On
- Velocity is tangent to a circular path.
- Centripetal acceleration points toward the center.
- ac = v2/r and Fc = mv2/r.
- Centripetal force is the net inward force, not a separate extra force.
- Different real forces can provide centripetal force: tension, friction, gravity, normal force, or combinations.
- For flat curves, static friction provides the inward force.
- For satellites, gravity provides the inward force.
- Universal gravitation follows F = Gm1m2/r2.
- Orbital speed for a circular orbit is v = √(GM/r).

